Question

Write an equation in stand form that goes through the poi (-1,2)(0,6)

Answer 1

To write the equation in standard form that goes through the points (-1,2) and (0,6), use the slope-intercept form of a linear equation, y = mx + b. Find the slope using the formula (y2 - y1) / (x2 - x1), substitute one of the points and the slope into the equation, and solve for the y-intercept.

Step-by-step explanation:

To write the equation in standard form that goes through the points (-1,2) and (0,6), we need to use the slope-intercept form of a linear equation, which is y = mx + b.

1. First, find the slope of the line using the formula: slope (m) = (y2 - y1) / (x2 - x1). In this case, the points are (-1,2) and (0,6). So, the slope is (6 - 2) / (0 - (-1)) = 4 / 1 = 4.
2. Next, substitute one of the points and the slope into the slope-intercept form. Let's use the point (0,6). So, the equation becomes y = 4x + b, where b is the y-intercept.
3. Finally, substitute the x and y values of the chosen point into the equation, and solve for b. Using (0,6), we have 6 = 4(0) + b. By solving for b, we find that b = 6.

Therefore, the equation in standard form that goes through the points (-1,2) and (0,6) is y = 4x + 6.