Question

two trains leave townws 320 miles apart at the same time and travel towar each other. one train travels 10 mph slower than the other. if they meet in 2 hours, what is the rate of each train

Answer 1

The rate of the faster train is 85 mph and the rate of the slower train is 75 mph.

Step-by-step explanation:

Let's say the rate of the faster train is x mph. Since the other train is traveling 10 mph slower, its rate would be x - 10 mph.

In 2 hours, the combined distance covered by both trains must be equal to the initial distance between them, which is 320 miles.

We can set up the equation 2(x) + 2(x - 10) = 320 to represent this situation.

Simplifying the equation, we get 4x - 20 = 320, which can be further simplified to 4x = 340, and x = 85.

Therefore, the rate of the faster train is 85 mph, and the rate of the slower train is 85 - 10 = 75 mph.