Question

manuclear fission process, the mass efect was 1.2x 10-5kg.Calculate the nergy released.[Speed of light in acuum c-3x10 mls) A) 1.08x10 J B) 5.20x10 C) 1.08x10" D) 2.50x10" TERM​

Answer 1

The energy released in a nuclear fission process with a mass deficit of 1.2 x 10^-5kg is calculated using E = mc^2, resulting in 1.08 x 10^12 Joules. The Correct Answer is Option.A.

Step-by-step explanation:

The energy released in a nuclear fission process where the mass deficit is 1.2 x 10-5kg can be calculated using Einstein’s famous equation E = mc2. To find the energy (E) in Joules (J), we multiply the mass deficit (m) by the speed of light squared (c2), where c is 3 x 108 meters per second (m/s).

So, the calculation would be:

E = (1.2 x 10-5 kg) x (3 x 108 m/s)2 = 1.08 x 1012 J

Therefore, the energy released is 1.08 x 1012 Joules, which makes option A the correct answer.