Final Answer:
The probability that it will take 5 seconds or less for the person to drive on the highway is 0.62.
Step-by-step explanation:
To find the probability that it takes 5 seconds or less for the person to drive on the highway, we need to integrate the density function F defined by B) (H) = 0.25e^{-0.135^7} from 0 to 5 seconds.
Let x be the elapsed time in seconds. Then, the probability that it takes x seconds or less for the person to drive on the highway is given by:
P(X ≤ x) = ∫^x_0 F(t) dt
Substituting the given density function, we have:
P(X ≤ x) = ∫^x_0 0.25e^{-0.135^7} dt
Integrating this expression, we get:
P(X ≤ x) = -0.25e^{-0.135^7} |^x_0
P(X ≤ 5) = -0.25e^{-0.135^7} |^5_0
Simplifying this expression, we get:
P(X ≤ 5) = 1 - e^{-0.135^7} = 0.62
Therefore, the probability that it takes 5 seconds or less for the person to drive on the highway is 0.62. This means that there is a relatively high probability that it will take less than 5 seconds for the person to drive on the highway, indicating that there is not much congestion on the highway during this time period.