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Sizes of TVs are determined by a diagonal measurement of their screen. If a TV has a diagonal measurement of 55 and a height of 30 , what is the TV s width? Round answer to nearest whole number.

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Final answer:

To find the width of the TV with a diagonal measurement of 55 units and a height of 30 units, we can use the Pythagorean theorem. By substituting the given values into the equation, we find that the width is approximately 46 units.

Step-by-step explanation:

To find the width of the TV, we can use the Pythagorean theorem, which states that the square of the hypotenuse is equal to the sum of the squares of the other two sides in a right triangle. In this case, the diagonal measurement of the TV represents the hypotenuse, and the height and width represent the other two sides.

Let's denote the width of the TV as 'w'. We can set up the equation as follows:

w^2 = diagonal^2 - height^2

w^2 = 55^2 - 30^2

w^2 = 3025 - 900

w^2 = 2125

w = √(2125)

w ≈ 46

Therefore, the width of the TV is approximately 46 units.

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