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Vertex (10,0) passing through points (-1,10) in constant term

User Pochopsp
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Final answer:

To find the equation of a quadratic function, we can use the vertex form which is given as y=a(x-h)^2+k where (h,k) represents the coordinates of the vertex. Since the vertex is given as (10,0), the equation becomes: y=a(x-10)^2. To find the value of 'a', we can substitute the coordinates (-1,10) into the equation and solve for 'a'. Once we have the value of 'a', we can substitute it back into the equation to get the final equation of the quadratic function.

Step-by-step explanation:

To find the equation of a quadratic function, we can use the vertex form which is given as: y=a(x-h)^2+k where (h,k) represents the coordinates of the vertex. Since the vertex is given as (10,0), the equation becomes: y=a(x-10)^2.

To find the value of 'a', we can substitute the coordinates (-1,10) into the equation and solve for 'a'. Substituting x=-1 and y=10, we get the equation 10=a(-1-10)^2. Solving this equation gives us the value of 'a'.

Once we have the value of 'a', we can substitute it back into the equation to get the final equation of the quadratic function.

User Elezar
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