Question

The population of a certain town grows by 1.8% each year. If the population today is 79,896 , what will the population be in 18 years? Round your answer to the nearest person (whole number)

Answer 1

To find the future population of a town with a growth rate of 1.8% in 18 years from a base population of 79,896, we use the exponential growth formula P = P0(1 + r)^t, resulting in a future population of 109,396 people when rounded to the nearest whole number.

Step-by-step explanation:

To calculate the future population of a town growing at 1.8% per year from a current population of 79,896, we would use the formula for exponential growth P = P0(1 + r)^t, where P is the future population, P0 is the current population, r is the growth rate (expressed as a decimal), and t is the time in years.

For this problem:

• P0 = 79,896
• r = 0.018 (which is 1.8% as a decimal)
• t = 18 years

By inserting these values into the formula, we get:

P = 79,896(1 + 0.018)^18

Now, calculate the value within the parentheses first, then raise it to the power of 18, and finally multiply by 79,896:

P = 79,896(1.018)^18

P = 79,896 × (1.368616617676804)

P = 109,396.18003436503

To find the population rounded to the nearest whole number, we get P = 109,396 people.

Therefore, we expect the town's population to reach 109,396 people in 18 years.