Question

The vertex of the parabola given by the funct f(x)=x²+8x+16 is at the point (-4,0) following describes the range of this function

Answer 1

The range of the quadratic function f(x) = x² + 8x + 16, which has the vertex at (-4,0), is all real numbers greater than or equal to 0.

Step-by-step explanation:

The question pertains to determining the range of a quadratic function based on its vertex. The given quadratic function f(x) = x² + 8x + 16 has its vertex at the point (-4,0). Since a quadratic function in the form of f(x) = ax² + bx + c opens upwards (if a > 0), the vertex represents the minimum point on the graph. Thus, the range of the function is all real numbers greater than or equal to 0, as the y-value of the vertex is 0 and the parabola opens upwards from there.