Question

Find 2 consecutive negative odd intergers such that 6 times the first plus the square of the second equals -14

Answer 1

To find two consecutive negative odd integers such that 6 times the first plus the square of the second equals -14, let's define the first integer as x and the second integer as x+2. We can set up the equation: 6x + (x+2)^2 = -14. Using the quadratic formula, we find that the two consecutive negative odd integers are -1 and -3.

Step-by-step explanation:

To find two consecutive negative odd integers such that 6 times the first plus the square of the second equals -14, let's define the first integer as x and the second integer as x+2.

We can set up the equation: 6x + (x+2)^2 = -14.

Simplifying the equation, we get x^2 + 10x + 18 = 0.

Using the quadratic formula, we find the two possible values for x: -1 and -9.

Therefore, the two consecutive negative odd integers are -1 and -3.