Question

If f(x)=2x^(2)-5, then what is the remainder when f(x) is divided by x-10 ?

Answer 1

The remainder when f(x) = 2x^2 - 5 is divided by x - 10 is 2x^2 - 40x + 195.

Step-by-step explanation:

To find the remainder when f(x) = 2x^2 - 5 is divided by x - 10, we can use the remainder theorem. According to the remainder theorem, if you substitute the divisor into the polynomial and evaluate it, you will get the remainder. So, substituting x - 10 into f(x), we get:

f(x) = 2(x - 10)^2 - 5

Expanding this equation gives:

f(x) = 2(x^2 - 20x + 100) - 5

f(x) = 2x^2 - 40x + 200 - 5

f(x) = 2x^2 - 40x + 195

This is the remainder when f(x) is divided by x - 10.