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Let aₙ be a sequence of real numbers such that aₙ = 3aₙ₋₁ + 2, with a₁ = 2, compute a₂.

User Elias
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Final answer:

To calculate a₂, we use the given formula aₙ = 3aₙ₋₁ + 2 and the initial value a₁ = 2, which gives us a₂ = 8.

Step-by-step explanation:

To compute a₂, the second term of the sequence, we use the given recursive formula aₙ = 3aₙ₋₁ + 2, with a₁ = 2. We plug in the value of a₁ to find a₂:

  • a₂ = 3a₁ + 2
  • a₂ = 3(2) + 2
  • a₂ = 6 + 2
  • a₂ = 8

User Wmmhihaa
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