Question

Given R and T are two mutually exclusive events of an experiment with P(R) = 0.48 and P(T) = 0.13, calculate the following probabilities.

a. P(Rᶜ) =

Answer 1

To find the probability of the complement of event R, P(R¹), you subtract P(R) from 1. Given P(R) = 0.48, P(R¹) is 0.52.

Step-by-step explanation:

You've asked to calculate the probability of the complement of event R, denoted as P(R⁽). Since R is a mutually exclusive event with T, we can use the definition of the complement of an event to find P(R⁽). The complement of an event signifies all outcomes that are not in the event. Therefore, the probability of the event and its complement always sum to 1.

Using this information:

• P(R) + P(R⁽) = 1
• P(R⁽) = 1 - P(R)
• P(R⁽) = 1 - 0.48
• P(R⁽) = 0.52

Therefore, the probability of not event R occurring or P(R⁽) is 0.52