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Find the special product using the formula for the difference of squares: (6y - (2/5))(6y + (2/5)).

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Final answer:

The special product of (6y - (2/5))(6y + (2/5)) is 36y^2 - 4/25.

Step-by-step explanation:

To find the special product using the formula for the difference of squares, we can expand the expression using the formula (a - b)(a + b) = a^2 - b^2. In this case, we have (6y - (2/5))(6y + (2/5)).

Applying the formula, we get (6y)^2 - (2/5)^2 = 36y^2 - 4/25.

Therefore, the special product of (6y - (2/5))(6y + (2/5)) is 36y^2 - 4/25.

User Gerald T
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