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Between The Points C=(1,-2) And N=(6,-5) The Nearest Hundredth.

1 Answer

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Final answer:

The distance between points C=(1,-2) and N=(6,-5) is approximately 5.83 units when rounded to the nearest hundredth.

Step-by-step explanation:

The question seems to be asking for the distance between points C=(1,-2) and N=(6,-5) on a Cartesian plane. To find the distance between two points, we can use the distance formula, which is derived from the Pythagorean theorem. This formula used for this question is:

Distance = √((x2-x1)2 + (y2-y1)2)

Applying the coordinates of C and N into the formula:

Distance = √((6-1)2 + (-5+2)2)

Distance = √(25 + 9)

Distance = √34

Distance ≈ 5.83 (rounded to the nearest hundredth)

User Jondykeman
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