139k views
3 votes
let z=x +iy. Express (1)/(2)-(1)/(4)i, (2)/(3)+(1)/(6)i is closest to the origin. Which is closest to 1+i?

User Catheline
by
8.2k points

1 Answer

5 votes

Final answer:

To find which complex number is closest to the origin, calculate the moduli of \((1/2)-(1/4)i\) and \((2/3)+(1/6)i\). To determine which is closest to \(1+i\), subtract \(1+i\) from each and then compute the moduli of the results.

Step-by-step explanation:

The student is asking which complex number, \((1/2)-(1/4)i\) or \((2/3)+(1/6)i\), is closest to the origin and which one is closest to \(1+i\). To determine the distances, we can calculate the modulus of each complex number (the distance from the origin) and then compare these values. To find the nearest complex number to \(1+i\), we can subtract this point from each complex number and again compute the modulus.

To calculate the modulus, use the formula \(|z| = \sqrt{x^2 + y^2}\) where z is a complex number of the form \(x+iy\). So for the first complex number, \(\sqrt{(1/2)^2 + (-1/4)^2}\) is computed to determine its distance from the origin. The second distance is calculated similarly. To ascertain proximity to \(1+i\), subtract \(1+i\) from each complex number, yielding \((1/2)-(3/4)i\) and \((2/3)-(1/3)i\), respectively, before calculating the modulus of these new complex numbers.

User Cmdkennedy
by
7.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories