18.3k views
3 votes
Y=-2x-5 pssing through point (3,-2) find equation for parallel line

User HSJ
by
7.6k points

1 Answer

2 votes

Final answer:

The equation of a line parallel to y = -2x - 5 and passing through the point (3, -2) is y = -2x + 4, since parallel lines have the same slope.

Step-by-step explanation:

To find the equation of a line parallel to the given line y = -2x - 5 and passing through the point (3, -2), you need to use the fact that parallel lines have the same slope. The slope of the given line is -2, because it is the coefficient of x in the equation. Therefore, the parallel line must also have a slope of -2.

Now you use the point-slope form of a line equation, which is y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point through which the line passes. Plugging in the slope -2 and the point (3, -2), you get:

y - (-2) = -2(x - 3)

Simplifying this, we get:

y + 2 = -2x + 6

Finally, subtracting 2 from both sides gives us the equation of the parallel line:

y = -2x + 4

User Unknownbits
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories