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For what value (s) of c is f(x)={(-cx+1, if x<2),(3, if x=2),(c^(2)x^(2)+2, if x>2):} continuous from the right at 2 .

User Paramore
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1 Answer

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Final answer:

For the function f(x) to be continuous from the right at x=2, the value of c must be ±1/2 to ensure the limit as x approaches 2 from the right is equal to f(2), which is 3.

Step-by-step explanation:

To determine for what value(s) of c the function f(x) is continuous from the right at x=2, we need to make sure that the limit of f(x) as x approaches 2 from the right is equal to f(2).

We are given that f(2) = 3, so for continuity from the right at x=2, the limit of the function f(x) as x approaches 2 from the right must also be equal to 3.

The function for x > 2 is c²x²+2. To find the limit as x approaches 2, we substitute x with 2:

c²(2)²+2 = c²·4+2 = 4c²+2.

To make the function continuous from the right at x=2, we set:

4c²+2 = 3

  • 4c² + 2 = 3
  • 4c² = 1
  • c² = 1/4
  • c = ±1/2

Therefore, the function is continuous from the right at x=2 when c is ±1/2.

User Jinghao Shi
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