60.6k views
0 votes
For what value (s) of c is f(x)={(-cx+1, if x<2),(3, if x=2),(c^(2)x^(2)+2, if x>2):} continuous from the right at 2 .

User Paramore
by
7.7k points

1 Answer

5 votes

Final answer:

For the function f(x) to be continuous from the right at x=2, the value of c must be ±1/2 to ensure the limit as x approaches 2 from the right is equal to f(2), which is 3.

Step-by-step explanation:

To determine for what value(s) of c the function f(x) is continuous from the right at x=2, we need to make sure that the limit of f(x) as x approaches 2 from the right is equal to f(2).

We are given that f(2) = 3, so for continuity from the right at x=2, the limit of the function f(x) as x approaches 2 from the right must also be equal to 3.

The function for x > 2 is c²x²+2. To find the limit as x approaches 2, we substitute x with 2:

c²(2)²+2 = c²·4+2 = 4c²+2.

To make the function continuous from the right at x=2, we set:

4c²+2 = 3

  • 4c² + 2 = 3
  • 4c² = 1
  • c² = 1/4
  • c = ±1/2

Therefore, the function is continuous from the right at x=2 when c is ±1/2.

User Jinghao Shi
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories