151k views
5 votes
Find the domain of f(x)=sqrt{-9 x+1}

1 Answer

4 votes

Final answer:

The domain of the function f(x) = \sqrt{-9x + 1} consists of all real numbers x such that x is less than or equal to 1/9.

Step-by-step explanation:

To find the domain of f(x) = \sqrt{-9x + 1}, we need to ensure that the expression under the square root is non-negative, since the square root of a negative number is not defined in the set of real numbers. This means we have to solve the inequality -9x + 1 ≥ 0.



Let's solve the inequality step-by-step:

  1. Start by adding 9x to both sides: 1 ≥ 9x.
  2. Then divide both sides by 9: \frac{1}{9} ≥ x.



This gives us our domain: x ≤ \frac{1}{9}. This means that the function f(x) is defined for all real values of x that are less than or equal to \frac{1}{9}.

User Rosenda
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories