151k views
1 vote
Put the following functions in order of smallest maximum value to largest maximum value. f(x)=-(x-3)^(2)+6

User Kyung Lee
by
8.3k points

1 Answer

2 votes

Final answer:

To put the functions in order of smallest maximum value to largest maximum value, we need to analyze the quadratic function and compare the vertex with the given options.

Step-by-step explanation:

To put the functions in order of smallest maximum value to largest maximum value, we need to analyze the function f(x)=-(x-3)^(2)+6. This function is in the form of a quadratic equation, and we can determine its maximum value by finding the vertex.

The vertex form of a quadratic equation is given by f(x) = a(x-h)^2 + k, where (h, k) is the vertex. Comparing this with the given function f(x)=-(x-3)^(2)+6, we can see that h=3 and k=6.

  1. Let's consider option a. y = 13x.
  2. Now let's consider option b. y = x².

Comparing the vertex of the given equation (-3, 6) with the graphs of the options, we can conclude that option a has the smallest maximum value, option b has the largest maximum value, and the given function f(x) is between them.

User Mortada
by
7.9k points