Final answer:
The equation of the line through (-3,3) parallel to y=0 is y=3. The equation of the line through (5,-2) perpendicular to x=0 is x=5.
Step-by-step explanation:
To find the equation of a line that is parallel to y=0 and passes through the point (-3,3), we know that parallel lines have the same slope. Since y=0 is a horizontal line and has a slope of 0, the parallel line will also have a slope of 0. The equation for a line with a slope of 0 is y=b, where b is the y-coordinate of any point on the line. So, the equation of the line through (-3,3) parallel to y=0 is y=3.
To find the equation of a line that is perpendicular to x=0 and passes through the point (5,-2), we know that perpendicular lines have slopes that are negative reciprocals of each other. Since x=0 is a vertical line and has an undefined slope, the perpendicular line will have a slope of 0. The equation for a line with a slope of 0 is x=a, where a is the x-coordinate of any point on the line. So, the equation of the line through (5,-2) perpendicular to x=0 is x=5.