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Find the zeros and the vertical intercept of the function f(x) = -4x^3 - 2x^2 + 2x.

User JGFMK
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Final answer:

To find the zeros of the function f(x) = -4x^3 - 2x^2 + 2x, set the function equal to zero and solve for x. The vertical intercept is the value of f(x) when x = 0.

Step-by-step explanation:

To find the zeros of the function f(x) = -4x^3 - 2x^2 + 2x, we set the function equal to zero and solve for x. Rearranging the equation, we get:

-4x^3 - 2x^2 + 2x = 0

Now, we can factor out an x: x(-4x^2 - 2x + 2) = 0

This gives us two possible solutions: x = 0 or -4x^2 - 2x + 2 = 0. To find the zeros of the quadratic equation, we can either factor it or use the quadratic formula.

The vertical intercept of the function is the value of f(x) when x = 0. Plugging in x = 0, we get:

f(0) = -4(0)^3 - 2(0)^2 + 2(0) = 0

User ARZ
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