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What are the x-intercepts for the function g(x) = x^3 + x^2 - 6x?

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Final answer:

To find the x-intercepts for the function g(x) = x^3 + x^2 - 6x, you factor the equation and solve for x, which yields the intercepts at 0, 2, and -3.

Step-by-step explanation:

The x-intercepts of a function are the values of x at which the function equals zero. To find the x-intercepts for the function g(x) = x^3 + x^2 - 6x, we need to set the function equal to zero and solve for x:

g(x) = 0

x^3 + x^2 - 6x = 0

First, factor out an x:

x(x^2 + x - 6) = 0

Now, factor the quadratic:

x(x - 2)(x + 3) = 0

Setting each factor equal to zero gives us the x-intercepts:

  • x = 0
  • x = 2
  • x = -3

Therefore, the x-intercepts of the function g(x) are 0, 2, and -3.

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