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Graphing an Exponential Function: f(x)=2x+3−4 and asked for a graph with domain, intercepts, horizontal asymptote

User Nerea
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Final answer:

To graph the exponential function f(x) = 2^x + 3 - 4, plot points and connect them to form a curve. The x-intercept is 0 and the y-intercept is (0, -4). There is no horizontal asymptote.

Step-by-step explanation:

To graph the exponential function f(x) = 2^x + 3 - 4, we need to plot points on the graph. Let's choose a few values for x and calculate the corresponding y values:

For x = 0, f(0) = 2^0 + 3 - 4 = 1 + 3 - 4 = 0

For x = 1, f(1) = 2^1 + 3 - 4 = 2 + 3 - 4 = 1

For x = 2, f(2) = 2^2 + 3 - 4 = 4 + 3 - 4 = 3

Plotting these points on a graph, we get a curve that starts at the point (0, 0) and goes through the points (1, 1) and (2, 3). The graph will continue in a similar manner.

The domain of this function is all real numbers, since the exponentiation can be done for any real number x. The x-intercept is the point where the function crosses the x-axis, which in this case is x = 0. The y-intercept is the point where the function crosses the y-axis, which is at (0, -4).

Since the function is exponential, it does not have a horizontal asymptote.

User Robin Lobel
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