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If (x+2)²+(y-4)²=k²((3x+y+2)²)/(100) represents a hyperbola then the minimum integral value of k is

User Trajan
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Final answer:

The minimum integral value of k in the given hyperbola equation is 1.

Step-by-step explanation:

The given equation represents a hyperbola. To find the minimum integral value of k, we need to analyze the equation further.

By comparing it to the standard form of a hyperbola, (x-h)²/a² - (y-k)²/b² = 1, we can see that:

  • a² = k²(3x+y+2)²/100
  • b² = k²

Since a hyperbola is symmetrical, its minimum value of k occurs when the smaller denominator between a² and b² is chosen. In this case, b² = k², so the minimum integral value of k is 1.

User Anuvrat Tiku
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