Final Answer:
1. For f(x,y) = 6 + x - y, contour lines are straight lines with a slope of -1 in the xy-plane.
2. Contour lines for f(x,y) =
form parabolic curves parallel to the x-axis, and for z = 4 -
, they are circles centered at the origin with decreasing radii as z decreases.
Step-by-step explanation:
1. For f(x,y) = 6 + x - y, the contour lines can be visualized as straight lines with a slope of -1 in the xy-plane. Each contour line represents points where the function has a constant value. The slope of -1 indicates that for every unit increase in x, there is a unit decrease in y, resulting in diagonal lines.
2. The function f(x,y) =
produces contour lines that are parabolic curves parallel to the x-axis. These curves represent points where the function has a constant value of
, creating a family of parabolas along the y-axis.
3. The contour lines for
are circular in shape and centered at the origin. As z decreases, the circles expand, depicting points where the function has a constant value. This pattern is characteristic of a surface defined by a quadratic function.
4. The function
generates concentric circles centered at the origin, with the radius increasing as z increases. These circles represent points where the function has a constant value, illustrating the radial symmetry of the surface.
5. The contour lines for f(x,y) =
take the form of hyperbolas centered along the x-axis. These hyperbolas represent points where the function has a constant value, exhibiting a pattern shaped by the interaction between x and y.