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Find the most general antiderivative of the function. (Check your answer by differentiation. Use C for the constant of the antiderivative. )
f(x)=√(7)+√(x)

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Final answer:

The most general antiderivative of the function f(x) = √7 + √x is √7x + (2/3)x^(3/2) + C.

Step-by-step explanation:

To find the most general antiderivative of the function f(x) = √7 + √x, we can treat the two terms separately:

The antiderivative of √7 is √7x, because when we take the derivative of this function, the √7 term becomes zero. The constant of integration (C) is added to account for any possible constant term in the original function.

The antiderivative of √x is (2/3)x^(3/2), as we add 1 to the exponent (1/2) and divide by the new exponent (3/2). Again, the constant of integration (C) is added.

Combining both antiderivatives, the most general antiderivative of f(x) = √7 + √x is √7x + (2/3)x^(3/2) + C.

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