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If f(x)=19 x²-x³, what is the rate of change of f'(x) at (1,18) ?

User Utiq
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Final answer:

The rate of change of f'(x) at (1,18) is found by evaluating the second derivative of f(x) at x=1, which yields a value of 32.

Step-by-step explanation:

The rate of change of f'(x) at a point is given by its derivative, which in this case is the second derivative of f(x) since f'(x) represents the first derivative. To find this, we need to differentiate f(x) = 19x² - x³ twice.

First, find the first derivative:

f'(x) = d/dx(19x² - x³) = 38x - 3x²

Now, find the second derivative:

f''(x) = d/dx(38x - 3x²) = 38 - 6x

The rate of change of f'(x) at the point (1,18) is the value of f''(1):

f''(1) = 38 - 6(1) = 38 - 6 = 32

Therefore, the rate of change of f'(x) at (1,18) is 32.

User Allenwoot
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