Final answer:
To compute the Riemann sum of the function f(x) = x^3 over [1,2] with two subintervals, we evaluate the function at the left endpoints of subintervals with width 0.5, giving a Riemann sum of 2.19 after rounding to two decimal places.
Step-by-step explanation:
To calculate the Riemann sum for the function f(x) = x3 over the interval [1,2] with two subintervals (n = 2), first, we need to determine the width of each subinterval, which is the length of the interval [1,2] divided by the number of subintervals, that is, (2 - 1) / 2 = 0.5. The left endpoints for these subintervals are x1 = 1 and x2 = 1.5. We then evaluate the function at these left endpoints and multiply by the width of the subintervals to get the approximate area under the curve.
The Riemann sum S is calculated as: S = f(x1)*width + f(x2)*width = (1)3*0.5 + (1.5)3*0.5 = 0.5 + 1.6875 = 2.1875. Rounded to two decimal places, the Riemann sum is 2.19.