The directrix, focus, and vertex of the parabola are y = 4, (-1, 2) and (-1, 1), respectively
Identifying the directrix, focus, and vertex of the parabola
From the question, we have the following parameters that can be used in our computation:
- Points = (-3, 3) & (1, -1).
- Point below the parabola = (-3, 2).
- Line above the parabola = (-3, 4) & (0, 4)
The vertex is the midpoint of the line connecting the focus and the directrix.
So, we have the vertex to be
(h, k) = (-3 + 1, 3 - 1)/2
(h, k) = (-1, 1)
Since the point (-3, 2) is below the parabola and lies on the axis of symmetry, the distance from the vertex to the focus is 1 unit (from the vertex to the point (−3, 2)).
So, we have the focus to be
Focus = (-1, 1 + 1)
Focus = (-1, 2)
The directrix is a horizontal line that is symmetrically opposite to the focus with respect to the vertex.
Since the given line above the parabola passes through (-3, 4) and (0, 4), the directrix is the horizontal line y = 4