Final answer:
To find the probability of rolling exactly a 6 on the first die or a 2 or larger on the second die, we need to calculate the individual probabilities and then add them together.
Step-by-step explanation:
To find the probability of rolling exactly a 6 on the first die or a 2 or larger on the second die, we need to determine the number of favorable outcomes and divide it by the total number of possible outcomes.
For the first die to roll exactly a 6, there is only 1 favorable outcome out of 20 possible outcomes (since it is a 20-sided die). So the probability of rolling a 6 on the first die is 1/20.
For the second die to roll a 2 or larger, there are 9 favorable outcomes out of 10 possible outcomes (since it is a 10-sided die). So the probability of rolling a 2 or larger on the second die is 9/10.
To find the probability of either of these events occurring, we can use the additive rule of probability. Since the events are mutually exclusive (rolling a 6 on the first die automatically excludes rolling a 2 or larger on the second die, and vice versa), we can simply add the probabilities.
Therefore, the probability of rolling either exactly a 6 on the first die or a 2 or larger on the second die is (1/20) + (9/10) = 29/20 or approximately 0.65.