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Estimate the indicated derivative by any method. (Round your answer to three decimal places.)

g(t) = 3/t⁵
Estimate g'(1).

User Luxdvie
by
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1 Answer

1 vote

Final Answer:

The estimated value of
\( g'(1) \) for
\( g(t) = (3)/(t^5) \) is ( 15.000 ) (rounded to three decimal places).

Step-by-step explanation:

To estimate
\( g'(1) \), we can use the definition of the derivative:


\[ g'(t) = \lim_{{h \to 0}} (g(t + h) - g(t))/(h) \]

Apply this formula to
\( g(t) = (3)/(t^5) \):


\[ g'(t) = \lim_{{h \to 0}} ((3)/((t + h)^5) - (3)/(t^5))/(h) \]

Now, substitute ( t = 1 ) into this expression:


\[ g'(1) = \lim_{{h \to 0}} ((3)/((1 + h)^5) - (3)/(1^5))/(h) \]

Simplify further:

\
[ g'(1) = \lim_{{h \to 0}} ((3)/((1 + h)^5) - 3)/(h) \]

Now, compute the limit. As ( h ) approaches 0, the expression becomes
\( (3 - 3)/(0) \), which is an indeterminate form. Apply L'Hôpital's Rule, taking the derivative of the numerator and denominator with respect to ( h ):


\[ g'(1) = \lim_{{h \to 0}} ((d)/(dh)\left((3)/((1 + h)^5) - 3\right))/((d)/(dh)h) \]

After evaluating this expression, we find (g'(1) = 15.000) (rounded to three decimal places).

User Gabriel Petersson
by
6.7k points