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Given that f(x) = e^(-g(x)), g(8) = 0, g'(8) = -4, what is the value of f'(8)?

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Final answer:

To find f'(8), we use the chain rule and given values of g(8) and g'(8) to calculate the derivative of f(x). The derivative of f(x) is -4, so f'(8) = -4.

Step-by-step explanation:

To find the value of f'(8), we need to use the chain rule. The chain rule states that if we have a composite function f(g(x)), then the derivative of f(g(x)) with respect to x is f'(g(x)) * g'(x). In this case, f(x) = e^(-g(x)), so we need to find the derivative of e^(-g(x)).

Let's start by finding the derivative of the inner function g(x). We are given that g(8) = 0 and g'(8) = -4. So g(x) = 0 and g'(x) = -4 everywhere.

Now, let's find the derivative of f(x). The derivative of e^x is e^x. So f'(x) = e^(-g(x)) * g'(x) = e^0 * (-4) = -4.

Therefore, f'(8) = -4.

User SteveSarsawa
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