195k views
1 vote
Find the general solution for the exact DE: 2t - y - (2y^(-3) + t)(dy/dt) = 0.

1 Answer

4 votes

Final answer:

To solve the exact differential equation, we verify exactness using the M and N functions, integrate with respect to the appropriate variables, and find the potential function whose level curves give us the general solution.

Step-by-step explanation:

To find the general solution for the given exact differential equation (DE), 2t - y - (2y^{-3} + t)(dy/dt) = 0, let's first verify its exactness and then solve it step by step.

First, we identify the function M(t, y) = 2t - y and the function N(t, y) = -(2y^{-3} + t) so that our DE looks like M(t, y) + N(t, y)*(dy/dt) = 0. We then confirm that ∂M/∂y = ∂N/∂t to ensure it's exact, which in this case should be true.

Next, we integrate M with respect to t and N with respect to y to find the potential function Ψ(t, y) such that ∂Ψ/∂t = M and ∂Ψ/∂y = N. Then the general solution will be given by the equation Ψ(t, y) = C, where C is a constant.

Following this procedure methodically will yield the general solution to the exact DE.

The process of finding and using the N and M functions, confirming the exactness, integrating, and finding the constant C are what help us arrive at the general solution for the DE.

User Keronda
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories