Final answer:
The slope of the tangent line to the parabola y = 3x² - 2x + 3 at the point where x = -1 is -8.
Step-by-step explanation:
The slope of the tangent line to the parabola y = 3x² - 2x + 3 at the point where x = -1 can be found using the derivative of the function. The derivative of y = 3x² - 2x + 3 is y' = 6x - 2. To find the slope at x = -1, substitute -1 into the derivative: y'(-1) = 6(-1) - 2 = -6 - 2 = -8. Therefore, the slope of the tangent line to the parabola at x = -1 is -8.