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Evaluate the indefinite integral: ∫ (5x + 1)/((x + 2)(x² - 2x + 1)) dx.

User Naydichev
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Final answer:

To evaluate the indefinite integral, we can decompose the fraction into partial fractions. After equating coefficients, we can integrate each term separately.

Step-by-step explanation:

To evaluate the indefinite integral, we need to decompose the fraction into partial fractions. The denominator factorizes into (x + 2)(x - 1)(x - 1). Therefore, the partial fraction decomposition is:

(5x + 1)/((x + 2)(x - 1)(x - 1)) = A/(x + 2) + B/(x - 1) + C/(x - 1)

Multiplying through by the common denominator, we get:

5x + 1 = A(x - 1)(x - 1) + B(x + 2)(x - 1) + C(x + 2)

Expanding and equating coefficients, we find that A = 2, B = 1, and C = -1.

Now, we can integrate each term separately:

∫ A/(x + 2) dx = 2ln|x + 2| + K1

∫ B/(x - 1) dx = ln|x - 1| + K2

∫ C/(x - 1) dx = -ln|x - 1| + K3

Therefore, the indefinite integral of (5x + 1)/((x + 2)(x - 1)(x - 1)) dx is 2ln|x + 2| + ln|x - 1| - ln|x - 1| + C, where C is the constant of integration.

User Armynante
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