Question

What is y=x^2-9x+4 in vertex form?

Answer 1

`y=\left(x^2-(9)/(2)\right)^2-(65)/(4)`

Explanation:

To put this in vertex form, we need to create a perfect square polynomial within the right side of the equation.

`y=x^2-9x+4`

`y=\left(x^2-9x + \left(-(9)/(2)\right)^2\right)+4 - (81)/(4)`

`y=\left(x^2-(9)/(2)\right)^2+4 - (81)/(4)`

`y=\left(x^2-(9)/(2)\right)^2-(65)/(4)`