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F(x)=(7x)/ˣ²)-16) your choice. The equation (s) of the horizontal asy

User Gakio
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Final answer:

The horizontal asymptote of the function (7x)/(x²-16) is y = 7, as it is determined by the ratio of the leading coefficients of the numerator and the denominator when they are of the same degree.

Step-by-step explanation:

It appears there is an error in the student's question regarding the function notation that is intended to ask about the equation(s) of the horizontal asymptote of a given function. However, assuming the function is (7x)/(x²-16), which seems likely from the given information, the horizontal asymptote can be determined by analyzing the behavior of the function as x tends towards infinity. For rational functions where the degree of the numerator is equal to the degree of the denominator, the horizontal asymptote is found by dividing the leading coefficients. In this case, since the degrees are equal, the horizontal asymptote is y = 7/1, which simplifies to y = 7.

User Keyan P
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