168k views
4 votes
Z varies jointly as y and the cube of x,z=336 when x=2 and y=-6

User John Kealy
by
8.6k points

1 Answer

4 votes

Final answer:

To find the joint variation of z with y and the cube of x, establish the equation z = kxy³ and use the given values to solve for the constant k. When x=2 and y=-6, z equals 336, from which we find k = -7.

Step-by-step explanation:

The question asks to establish a relationship where z varies jointly as y and the cube of x. This means that z = kxy³, where k is the constant of proportionality. We are given that z = 336 when x = 2 and y = -6. To find the constant k, we can substitute these values into the equation: 336 = k(-6)(2)³. Simplifying, we get k = 336 / (-6)(8), which results in k = -7. Now that we have the constant, the equation modeling the relationship is z = -7xy³.

User Thispatchofsky
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories