Final answer:
To find the equation of a line perpendicular to y=3x-2 that passes through (-1,2), use the point-slope form of a linear equation.
Step-by-step explanation:
To find the equation of a line perpendicular to y=3x-2, we first need to determine the slope of the given line. The slope of y=3x-2 is 3. Since perpendicular lines have slopes that are negative reciprocals, the slope of the line perpendicular to y=3x-2 would be -1/3. Now, we can use the point-slope form of a linear equation to find the equation of the line that passes through (-1,2) with a slope of -1/3. Using the point-slope form, the equation can be written as y-2 = -1/3(x+1).