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Find the equation of the line perpendicular to y=3x-2. that passes through (-1,2).

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Final answer:

To find the equation of a line perpendicular to y=3x-2 that passes through (-1,2), use the point-slope form of a linear equation.

Step-by-step explanation:

To find the equation of a line perpendicular to y=3x-2, we first need to determine the slope of the given line. The slope of y=3x-2 is 3. Since perpendicular lines have slopes that are negative reciprocals, the slope of the line perpendicular to y=3x-2 would be -1/3. Now, we can use the point-slope form of a linear equation to find the equation of the line that passes through (-1,2) with a slope of -1/3. Using the point-slope form, the equation can be written as y-2 = -1/3(x+1).

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