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Given y' = 4x², find the change in y, denoted as Δy, when x is equal to 4 and Δx is equal to 0.2. Find the differential dy.

User Yoniyes
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Final answer:

The change in y (Δy) is equal to 64 when x is equal to 4 and Δx is equal to 0.2. The differential dy is equal to 12.8.

Step-by-step explanation:

To find the change in y (Δy) when x is equal to 4 and Δx is equal to 0.2, we can use the derivative of y with respect to x. Given y' = 4x², we can substitute the values of x and Δx into the derivative:

y' = 4(4)² = 4(16) = 64.

Therefore, the change in y (Δy) is equal to 64 when x is equal to 4 and Δx is equal to 0.2.

To find the differential dy, we can use the derivative y' = 4x². The differential dy is given by dy = y' * dx. Substituting y' = 4x² and Δx = 0.2 into the differential formula:

dy = 4(4)² * 0.2 = 4(16) * 0.2 = 64 * 0.2 = 12.8.

User JohannesR
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