Final answer:
To write a polynomial function f(x) that is second-degree and has zeros at x=2 and x=-3 and f(7)=-6, use the factored form of the quadratic equation. The function is f(x) = (-3/25)(x-2)(x+3)
Step-by-step explanation:
To write a polynomial function in standard form given the zeros and a point, we can use the factored form of the quadratic equation. The zeros are x=2 and x=-3, so the factors of the quadratic function are (x-2) and (x+3). To find the value of the leading coefficient, we can use the point (7,-6) by substituting the values into the function and solving for the coefficient.
f(x) = a(x-2)(x+3)
-6 = a(7-2)(7+3)
-6 = a(5)(10)
-6 = 50a
a = -6/50 = -3/25
Therefore, the polynomial function is f(x) = (-3/25)(x-2)(x+3)