Question

Divide. (16x³-16x²+23x-7)÷(4x²-x)

Answer 1

To divide (16x³-16x²+23x-7) by (4x²-x), follow the long division process. The quotient is 4x -29 +7/(4x²-x).

Step-by-step explanation:

To divide (16x³-16x²+23x-7) by (4x²-x), we can use long division:

1. Divide the first term of the numerator (16x³) by the first term of the denominator (4x²). The result is 4x.
2. Multiply the entire denominator (4x²-x) by 4x and subtract it from the numerator (16x³-16x²+23x-7). The result is 16x³ - 16x² +21x - 7.
3. Now, we will repeat the process with the new numerator (16x³ - 16x² + 21x - 7) and the denominator (4x²-x).
4. Divide the first term of the new numerator (16x³) by the first term of the denominator (4x²). The result is 4x.
5. Multiply the entire denominator (4x²-x) by 4x and subtract it from the new numerator (16x³ - 16x² + 21x - 7). The result is -29x + 7.

Therefore, (16x³-16x²+23x-7) divided by (4x²-x) is equal to 4x -29 + 7/(4x²-x).