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A point on a line and its slope are given. Find the pe P=(3,2);m=-(2)/(3)

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Final answer:

To find the equation of a line given a point (3,2) and a slope of -2/3, the point-slope formula is used, resulting in the final equation of the line as y = -(2/3)x + 4.

Step-by-step explanation:

The student is asking how to find the equation of a line given a point on the line and its slope. Given a point P=(3,2) and a slope m=-2/3, the equation of the line can be found using the point-slope form of a line: y - y1 = m(x - x1).

Plugging the supplied values into the point-slope form yields the equation:

y - 2 = -(2/3)(x - 3)

Which simplifies to:

y = -(2/3)x + 2 + 2

Therefore, the equation of the line is y = -(2/3)x + 4.

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