Question

For the function f(x,y)=x2y on the interior of the circle x2+y2=4 with −1

Answer 1

The value of the function on the interior of the given circle is 1.

Step-by-step explanation:

The given function is f(x,y) = x^2y. We are asked to find the value of the function on the interior of the circle x^2 + y^2 = 4 with -1 < x < 1.

To find the value of the function, we need to substitute the values of x and y into the function. Since we are only interested in the interior of the circle, we need to consider the values of x and y that satisfy the circle equation and the given conditions.

By substituting x = -1 and y = 1 into the function, we get f(-1,1) = (-1)^2 * 1 = 1. Therefore, the value of the function on the interior of the circle with -1 < x < 1 is 1.