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Find the directional derivative of the function f(x,y,z)=xyz​ in the direction of u=(6,2,−9). The provided answer format seems incomplete

User Paxal
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Final Answer:

The directional derivative of the function f(x, y, z) = xyz in the direction of u = (6, 2, -9) is -11x² + 6yz - 11xz.

Step-by-step explanation:

The directional derivative of a scalar field f at a point p in the direction of a vector u is given by the formula:

∇f · u = Duf = ∂f/∂x * ux + ∂f/∂y * uy + ∂f/∂z * uz

where ∇f is the gradient of f, ux, uy, and uz are the components of u.

In this case, we have:

f(x, y, z) = xyz

∇f = (yz, xz, xy)

u = (6, 2, -9)

Therefore, the directional derivative Duf is calculated as follows:

Duf = ∇f · u = (yz, xz, xy) · (6, 2, -9)

= yz * 6 + xz * 2 + xy * (-9)

= -11x² + 6yz - 11xz

Therefore, the directional derivative of the function f(x, y, z) = xyz in the direction of u = (6, 2, -9) is -11x² + 6yz - 11xz.

User Yokoloko
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