137k views
5 votes
Find an equation in rectangular coordinates for the spherical equation p=2csc(phi)csc(theta). The answer is not 3x^2+3y^2-z^2=0

User Gaitat
by
8.1k points

1 Answer

1 vote

Final answer:

To find an equation in rectangular coordinates for the spherical equation p=2csc(phi)csc(theta), we need to use the relationships between spherical and rectangular coordinates.

Step-by-step explanation:

To find an equation in rectangular coordinates for the spherical equation p=2csc(phi)csc(theta), we need to use the relationships between spherical and rectangular coordinates. The relationship between rectangular and spherical coordinates is x = r sin(theta) cos(phi), y = r sin(theta) sin(phi), and z = r cos(theta).

Substituting the given spherical equation, p=2csc(phi)csc(theta), into the rectangular coordinate equations, we get x = 2cot(phi)csc(theta)cos(phi), y = 2cot(phi)csc(theta)sin(phi), and z = 2csc(theta).

Thus, the equation in rectangular coordinates for the given spherical equation is x = 2cot(phi)csc(theta)cos(phi), y = 2cot(phi)csc(theta)sin(phi), and z = 2csc(theta).

User Yeonsu
by
7.9k points