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Water from two ponds are being drained out. Pond A contains

100,000 litres of water and pond B contains 120,000 litres of
water. Water runs out from pond A at 2,000 litres per day, and
water runs out

User IVlad
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1 Answer

3 votes

Final answer:

It would take approximately 22.22 hours to fill a swimming pool with a capacity of 80,000 liters using a garden hose delivering 60 L/min. If you could divert a river flowing at 5000 m³/s, the pool would be filled almost instantaneously, in about 0.016 seconds.

Step-by-step explanation:

To estimate the time it would take to fill a private swimming pool with a capacity of 80,000 liters using a garden hose that delivers 60 liters per minute, we first need to calculate the total amount of time needed. We use the formula:

Time = Volume / Flow rate

For our case:

Time = 80,000 L / (60 L/min)

Time = 1,333.33 min

To convert minutes to hours, we divide by 60:
Time = 1,333.33 min / 60

Time = 22.22 hours

So, it would take approximately 22.22 hours to fill the pool with the garden hose.

For the second part, filling the pool with a river flowing at 5000 m³/s would be instantaneous from a practical standpoint, since this flow rate is tremendously larger than the capacity of the pool.

1 m³ = 1,000 liters, therefore:

Flow rate of river = 5000 m³/s * 1,000 L/m³

Flow rate of river = 5,000,000 L/s

For an 80,000 L pool, the river would fill it in:

Time = 80,000 L / 5,000,000 L/s

Time = 0.016 seconds

The pool would be filled almost instantaneously (0.016 seconds).

User Quima
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