Question

Solve the fallowing equation

A f(x)=-2 x^{3}+ {1}{x^{2} ; x=-1
B f(x)=x^{4}-3 x^{3}+2 x^{2}-6 ; x=2
C f(x)=x-{1}{x^{2} ; x=1
D f(x)=x^{3}+ √ {x} ; x=4
E f(x)=-{1}{3} x^{3}+ √{8 x} ; x=2

Answer 1

To solve each equation, substitute the given value of x into the function f(x) and perform the calculations. That way, we can find the value of f(x) at the given x.

Step-by-step explanation:

To solve each equation, substitute the given value of x into the function f(x) and perform the calculations.

A.

f(x) = -2x^3 + 1/x^2

f(-1) = -2(-1)^3 + 1/(-1)^2

f(-1) = -2(-1) + 1/1

f(-1) = 2 + 1

f(-1) = 3

B.

f(x) = x^4 - 3x^3 + 2x^2 - 6

f(2) = (2)^4 - 3(2)^3 + 2(2)^2 - 6

f(2) = 16 - 3(8) + 2(4) - 6

f(2) = 16 - 24 + 8 - 6

f(2) = -6

C.

f(x) = x - 1/x^2

f(1) = 1 - 1/(1)^2

f(1) = 1 - 1/1

f(1) = 1 - 1

f(1) = 0

D.

f(x) = x^3 + √x

f(4) = (4)^3 + √(4)

f(4) = 64 + 2

f(4) = 66

E.

f(x) = -1/3x^3 + √(8x)

f(2) = -1/3(2)^3 + √(8(2))

f(2) = -1/3(8) + √16

f(2) = -8/3 + 4

f(2) = -8/3 + 12/3

f(2) = 4/3