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(3)/(x²-x-2)-(2)/(x²+x-6) inal expression. You may leave the deno

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Final answer:

To simplify the given algebraic expression, factor the denominators to find a common denominator and then combine the fractions. After finding and multiplying by the common denominators, subtract the numerators, and simplify further to obtain the final expression.

Step-by-step explanation:

Simplifying Algebraic Fractions

The given algebraic expression is:

(3)/(x²-x-2) - (2)/(x²+x-6)

To simplify this expression, we need to factor the denominators and find a common denominator so that we can combine the two fractions. First, we factor the quadratic expressions:

  • x² - x - 2 can be factored into (x - 2)(x + 1).
  • x² + x - 6 can be factored into (x + 3)(x - 2).

The common denominator will be the product of (x - 2), (x + 1), and (x + 3). Now we need to adjust each fraction by multiplying to have this common denominator:

  • For (3)/(x²-x-2), multiply by ((x + 3)/(x + 3)) to get (3(x + 3))/((x - 2)(x + 1)(x + 3)).
  • For (2)/(x²+x-6), multiply by ((x + 1)/(x + 1)) to get (2(x + 1))/((x - 2)(x + 1)(x + 3)).

Combining the adjusted fractions gives us:

((3(x + 3)) - (2(x + 1)))/((x - 2)(x + 1)(x + 3))

This simplification allows us to subtract the numerators. To further simplify, distribute the numerals through the parenthesis:

  • 3(x + 3) becomes 3x + 9.
  • 2(x + 1) becomes 2x + 2.

The final simplified expression is:

((3x + 9) - (2x + 2))/((x - 2)(x + 1)(x + 3))/

Which simplifies further to:

(x + 7)/((x - 2)(x + 1)(x + 3))

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