Final answer:
The axis of symmetry of the equation f(x) = x² + 8x - 12 is x = -4.
Step-by-step explanation:
The axis of symmetry of a quadratic equation in the form f(x) = ax² + bx + c is given by the formula x = -b / (2a).
In the equation f(x) = x² + 8x - 12:
a = 1, b = 8, and c = -12.
Substituting these values into the formula, we get x = -8 / (2*1) = -4.
Therefore, the axis of symmetry of the equation is x = -4.